Thus, the angular acceleration and the time interval are both too large. (c) It would be difficult for a human being to spin a ball with such a large angular acceleration and especially for this length of time. (a) What is the final angular velocity if the ball starts from rest and the acceleration lasts 2 s? (b) What is unreasonable about the result? (c) Which premises are unreasonable or inconsistent? Solution 2 2 (a) Given:, )(2 s) (b) This is approximately 32 revolutions of the ball each second. Unreasonable Results You are told that a basketball player spins the ball with an 2 angular acceleration of 100.
(a) 90 rev rad 1 min 2 02, so that min rev 60 s 2 02 (0 2 (9 2 2( 0 2 ) 1 rev rad rev rev rad (b) 4. (b) How many turns will the stone make before coming to rest? Solution 1 f k N 0 N) N. (a) Assuming the kinetic coefficient of friction between steel and stone is 0, calculate the angular acceleration of the grindstone. Integrated Concepts You have a grindstone (a disk) that is 90 kg, has a radius, and is turning at 90 rpm, and you press a steel axe against it with a radial force of 20 N.
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(a) What is its angular acceleration in ? (b) What is the tangential acceleration of a point 9 cm from the axis of rotation? (c) What is the radial 2 acceleration in and multiples of g of this point at full rpm? Solution rad 1 min 4 1 rev 60 s 4 1 t 2 2 120 s (a) 5 2 2 (b) a t )(0 m) v 2 r 2 2 r r m)(1 4 2 7 2 7 2 (c) 1 2 gs 2 9 OpenStax College Physics Instructor Solutions Manual Chapter 10 3. Integrated Concepts An ultracentrifuge accelerates from rest to rpm in 2 2 min. What is its angular velocity in revolutions per second? Solution 500 km 1h m 1h 3600 s 1 km v 138 r 30 m 1 rev rad 2. At its peak, a tornado is 60 m in diameter and carries 500 winds. Vista previa del texto OpenStax College Physics Instructor Solutions Manual Chapter 10 CHAPTER 10: ROTATIONAL MOTION AND ANGULAR MOMENTUM 10 ANGULAR ACCELERATION 1.
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